Optimal. Leaf size=136 \[ -\frac{1}{2} b^3 c^2 \text{PolyLog}\left (2,\frac{2}{c x^3+1}-1\right )+b^2 c^2 \log \left (2-\frac{2}{c x^3+1}\right ) \left (a+b \tanh ^{-1}\left (c x^3\right )\right )+\frac{1}{2} b c^2 \left (a+b \tanh ^{-1}\left (c x^3\right )\right )^2+\frac{1}{6} c^2 \left (a+b \tanh ^{-1}\left (c x^3\right )\right )^3-\frac{b c \left (a+b \tanh ^{-1}\left (c x^3\right )\right )^2}{2 x^3}-\frac{\left (a+b \tanh ^{-1}\left (c x^3\right )\right )^3}{6 x^6} \]
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Rubi [F] time = 1.57491, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{\left (a+b \tanh ^{-1}\left (c x^3\right )\right )^3}{x^7} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int \frac{\left (a+b \tanh ^{-1}\left (c x^3\right )\right )^3}{x^7} \, dx &=\int \left (\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{8 x^7}+\frac{3 b \left (-2 a+b \log \left (1-c x^3\right )\right )^2 \log \left (1+c x^3\right )}{8 x^7}-\frac{3 b^2 \left (-2 a+b \log \left (1-c x^3\right )\right ) \log ^2\left (1+c x^3\right )}{8 x^7}+\frac{b^3 \log ^3\left (1+c x^3\right )}{8 x^7}\right ) \, dx\\ &=\frac{1}{8} \int \frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{x^7} \, dx+\frac{1}{8} (3 b) \int \frac{\left (-2 a+b \log \left (1-c x^3\right )\right )^2 \log \left (1+c x^3\right )}{x^7} \, dx-\frac{1}{8} \left (3 b^2\right ) \int \frac{\left (-2 a+b \log \left (1-c x^3\right )\right ) \log ^2\left (1+c x^3\right )}{x^7} \, dx+\frac{1}{8} b^3 \int \frac{\log ^3\left (1+c x^3\right )}{x^7} \, dx\\ &=\frac{1}{24} \operatorname{Subst}\left (\int \frac{(2 a-b \log (1-c x))^3}{x^3} \, dx,x,x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )+\frac{1}{24} b^3 \operatorname{Subst}\left (\int \frac{\log ^3(1+c x)}{x^3} \, dx,x,x^3\right )\\ &=-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )+\frac{1}{16} (b c) \operatorname{Subst}\left (\int \frac{(2 a-b \log (1-c x))^2}{x^2 (1-c x)} \, dx,x,x^3\right )+\frac{1}{16} \left (b^3 c\right ) \operatorname{Subst}\left (\int \frac{\log ^2(1+c x)}{x^2 (1+c x)} \, dx,x,x^3\right )\\ &=-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}-\frac{1}{16} b \operatorname{Subst}\left (\int \frac{(2 a-b \log (x))^2}{x \left (\frac{1}{c}-\frac{x}{c}\right )^2} \, dx,x,1-c x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )+\frac{1}{16} b^3 \operatorname{Subst}\left (\int \frac{\log ^2(x)}{x \left (-\frac{1}{c}+\frac{x}{c}\right )^2} \, dx,x,1+c x^3\right )\\ &=-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}-\frac{1}{16} b \operatorname{Subst}\left (\int \frac{(2 a-b \log (x))^2}{\left (\frac{1}{c}-\frac{x}{c}\right )^2} \, dx,x,1-c x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )+\frac{1}{16} b^3 \operatorname{Subst}\left (\int \frac{\log ^2(x)}{\left (-\frac{1}{c}+\frac{x}{c}\right )^2} \, dx,x,1+c x^3\right )-\frac{1}{16} (b c) \operatorname{Subst}\left (\int \frac{(2 a-b \log (x))^2}{x \left (\frac{1}{c}-\frac{x}{c}\right )} \, dx,x,1-c x^3\right )-\frac{1}{16} \left (b^3 c\right ) \operatorname{Subst}\left (\int \frac{\log ^2(x)}{x \left (-\frac{1}{c}+\frac{x}{c}\right )} \, dx,x,1+c x^3\right )\\ &=-\frac{b c \left (1-c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2}{16 x^3}-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 c \left (1+c x^3\right ) \log ^2\left (1+c x^3\right )}{16 x^3}-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{16} (b c) \operatorname{Subst}\left (\int \frac{(2 a-b \log (x))^2}{\frac{1}{c}-\frac{x}{c}} \, dx,x,1-c x^3\right )-\frac{1}{8} \left (b^2 c\right ) \operatorname{Subst}\left (\int \frac{2 a-b \log (x)}{\frac{1}{c}-\frac{x}{c}} \, dx,x,1-c x^3\right )-\frac{1}{16} \left (b^3 c\right ) \operatorname{Subst}\left (\int \frac{\log ^2(x)}{-\frac{1}{c}+\frac{x}{c}} \, dx,x,1+c x^3\right )+\frac{1}{8} \left (b^3 c\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{-\frac{1}{c}+\frac{x}{c}} \, dx,x,1+c x^3\right )-\frac{1}{16} \left (b c^2\right ) \operatorname{Subst}\left (\int \frac{(2 a-b \log (x))^2}{x} \, dx,x,1-c x^3\right )+\frac{1}{16} \left (b^3 c^2\right ) \operatorname{Subst}\left (\int \frac{\log ^2(x)}{x} \, dx,x,1+c x^3\right )\\ &=\frac{3}{4} a b^2 c^2 \log (x)-\frac{b c \left (1-c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2}{16 x^3}+\frac{1}{16} b c^2 \log \left (c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 c \left (1+c x^3\right ) \log ^2\left (1+c x^3\right )}{16 x^3}-\frac{1}{16} b^3 c^2 \log \left (-c x^3\right ) \log ^2\left (1+c x^3\right )-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}-\frac{1}{8} b^3 c^2 \text{Li}_2\left (-c x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )+\frac{1}{8} \left (b^3 c\right ) \operatorname{Subst}\left (\int \frac{\log (x)}{\frac{1}{c}-\frac{x}{c}} \, dx,x,1-c x^3\right )+\frac{1}{16} c^2 \operatorname{Subst}\left (\int x^2 \, dx,x,2 a-b \log \left (1-c x^3\right )\right )+\frac{1}{8} \left (b^2 c^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-x) (2 a-b \log (x))}{x} \, dx,x,1-c x^3\right )+\frac{1}{16} \left (b^3 c^2\right ) \operatorname{Subst}\left (\int x^2 \, dx,x,\log \left (1+c x^3\right )\right )+\frac{1}{8} \left (b^3 c^2\right ) \operatorname{Subst}\left (\int \frac{\log (1-x) \log (x)}{x} \, dx,x,1+c x^3\right )\\ &=\frac{3}{4} a b^2 c^2 \log (x)-\frac{b c \left (1-c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2}{16 x^3}+\frac{1}{16} b c^2 \log \left (c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2+\frac{1}{48} c^2 \left (2 a-b \log \left (1-c x^3\right )\right )^3-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 c \left (1+c x^3\right ) \log ^2\left (1+c x^3\right )}{16 x^3}-\frac{1}{16} b^3 c^2 \log \left (-c x^3\right ) \log ^2\left (1+c x^3\right )+\frac{1}{48} b^3 c^2 \log ^3\left (1+c x^3\right )-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}-\frac{1}{8} b^3 c^2 \text{Li}_2\left (-c x^3\right )+\frac{1}{8} b^3 c^2 \text{Li}_2\left (c x^3\right )-\frac{1}{8} b^2 c^2 \left (2 a-b \log \left (1-c x^3\right )\right ) \text{Li}_2\left (1-c x^3\right )-\frac{1}{8} b^3 c^2 \log \left (1+c x^3\right ) \text{Li}_2\left (1+c x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} \left (b^3 c^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,1-c x^3\right )+\frac{1}{8} \left (b^3 c^2\right ) \operatorname{Subst}\left (\int \frac{\text{Li}_2(x)}{x} \, dx,x,1+c x^3\right )\\ &=\frac{3}{4} a b^2 c^2 \log (x)-\frac{b c \left (1-c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2}{16 x^3}+\frac{1}{16} b c^2 \log \left (c x^3\right ) \left (2 a-b \log \left (1-c x^3\right )\right )^2+\frac{1}{48} c^2 \left (2 a-b \log \left (1-c x^3\right )\right )^3-\frac{\left (2 a-b \log \left (1-c x^3\right )\right )^3}{48 x^6}-\frac{b^3 c \left (1+c x^3\right ) \log ^2\left (1+c x^3\right )}{16 x^3}-\frac{1}{16} b^3 c^2 \log \left (-c x^3\right ) \log ^2\left (1+c x^3\right )+\frac{1}{48} b^3 c^2 \log ^3\left (1+c x^3\right )-\frac{b^3 \log ^3\left (1+c x^3\right )}{48 x^6}-\frac{1}{8} b^3 c^2 \text{Li}_2\left (-c x^3\right )+\frac{1}{8} b^3 c^2 \text{Li}_2\left (c x^3\right )-\frac{1}{8} b^2 c^2 \left (2 a-b \log \left (1-c x^3\right )\right ) \text{Li}_2\left (1-c x^3\right )-\frac{1}{8} b^3 c^2 \log \left (1+c x^3\right ) \text{Li}_2\left (1+c x^3\right )-\frac{1}{8} b^3 c^2 \text{Li}_3\left (1-c x^3\right )+\frac{1}{8} b^3 c^2 \text{Li}_3\left (1+c x^3\right )+\frac{1}{8} b \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x))^2 \log (1+c x)}{x^3} \, dx,x,x^3\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \frac{(-2 a+b \log (1-c x)) \log ^2(1+c x)}{x^3} \, dx,x,x^3\right )\\ \end{align*}
Mathematica [A] time = 0.27932, size = 218, normalized size = 1.6 \[ \frac{-6 b^3 c^2 x^6 \text{PolyLog}\left (2,e^{-2 \tanh ^{-1}\left (c x^3\right )}\right )+a \left (-2 a^2-3 a b c^2 x^6 \log \left (1-c x^3\right )+3 a b c^2 x^6 \log \left (c x^3+1\right )-6 a b c x^3+12 b^2 c^2 x^6 \log \left (\frac{c x^3}{\sqrt{1-c^2 x^6}}\right )\right )-6 b \tanh ^{-1}\left (c x^3\right ) \left (a^2+2 a b c x^3-2 b^2 c^2 x^6 \log \left (1-e^{-2 \tanh ^{-1}\left (c x^3\right )}\right )\right )+6 b^2 \left (c x^3-1\right ) \tanh ^{-1}\left (c x^3\right )^2 \left (a c x^3+a+b c x^3\right )+2 b^3 \left (c^2 x^6-1\right ) \tanh ^{-1}\left (c x^3\right )^3}{12 x^6} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.23, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( a+b{\it Artanh} \left ( c{x}^{3} \right ) \right ) ^{3}}{{x}^{7}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \,{\left ({\left (c \log \left (c x^{3} + 1\right ) - c \log \left (c x^{3} - 1\right ) - \frac{2}{x^{3}}\right )} c - \frac{2 \, \operatorname{artanh}\left (c x^{3}\right )}{x^{6}}\right )} a^{2} b + \frac{1}{8} \,{\left ({\left (2 \,{\left (\log \left (c x^{3} - 1\right ) - 2\right )} \log \left (c x^{3} + 1\right ) - \log \left (c x^{3} + 1\right )^{2} - \log \left (c x^{3} - 1\right )^{2} - 4 \, \log \left (c x^{3} - 1\right ) + 24 \, \log \left (x\right )\right )} c^{2} + 4 \,{\left (c \log \left (c x^{3} + 1\right ) - c \log \left (c x^{3} - 1\right ) - \frac{2}{x^{3}}\right )} c \operatorname{artanh}\left (c x^{3}\right )\right )} a b^{2} - \frac{1}{48} \, b^{3}{\left (\frac{{\left (c^{2} x^{6} - 1\right )} \log \left (-c x^{3} + 1\right )^{3} + 3 \,{\left (2 \, c x^{3} -{\left (c^{2} x^{6} - 1\right )} \log \left (c x^{3} + 1\right )\right )} \log \left (-c x^{3} + 1\right )^{2}}{x^{6}} + 6 \, \int -\frac{{\left (c x^{3} - 1\right )} \log \left (c x^{3} + 1\right )^{3} + 3 \,{\left (2 \, c^{2} x^{6} -{\left (c x^{3} - 1\right )} \log \left (c x^{3} + 1\right )^{2} -{\left (c^{3} x^{9} - c x^{3}\right )} \log \left (c x^{3} + 1\right )\right )} \log \left (-c x^{3} + 1\right )}{c x^{10} - x^{7}}\,{d x}\right )} - \frac{a b^{2} \operatorname{artanh}\left (c x^{3}\right )^{2}}{2 \, x^{6}} - \frac{a^{3}}{6 \, x^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b^{3} \operatorname{artanh}\left (c x^{3}\right )^{3} + 3 \, a b^{2} \operatorname{artanh}\left (c x^{3}\right )^{2} + 3 \, a^{2} b \operatorname{artanh}\left (c x^{3}\right ) + a^{3}}{x^{7}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{artanh}\left (c x^{3}\right ) + a\right )}^{3}}{x^{7}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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